19 Aug
2005
19 Aug
'05
8:39 a.m.
Hi! On Thu, Aug 18, 2005 at 03:01:07PM +0200, Vera Louise Hauge wrote:
a = a0 + x*a1; b = a0 + a1*x;
If the ex objects are evaluated (symbolically), such that a-b becomes 0, then the test would be finished.
However, how do I evaluate such a expression as a-b symbolically?
ex c = a - b;
Or are there other ways of comparing two such ex objects?
if (a == b) { ... } Bye, Christian -- / Physics is an algorithm \/ http://www.uni-mainz.de/~bauec002/