On 04/10/2016 12:23 AM, Vladimir V. Kisil wrote:
On Sat, 9 Apr 2016 23:59:36 +0200, "Richard B. Kreckel" <kreckel@in.terlu.de> said: >> f(x,y).diff(x, 3).diff(y, 2) >> which is printed as >> D[0,0,0,1,1](f)(x,y) >> This is fantastic.
RK> Hmmm... Wouldn't it be more fantastic if it were printed RK> D[x,x,x,y,y](f)(x,y)?
But how to print f(x+y,x-y).diff(x, 3).diff(y, 2) in this case?
Well, I would have supposed like this: D[x+y,x+y,x+y,x+y,x+y](f)(x+y,x-y)+D[x+y,x+y,x+y,x+y,x-y](f)(x+y,x-y)-2*D[x+y,x+y,x+y,x-y,x-y](f)(x+y,x-y)-2*D[x+y,x+y,x-y,x-y,x-y](f)(x+y,x-y)+D[x+y,x-y,x-y,x-y,x-y](f)(x+y,x-y)+D[x-y,x-y,x-y,x-y,x-y](f)(x+y,x-y) A trivial patch is attached. All my best, -richy. -- Richard B. Kreckel <http://in.terlu.de/~kreckel/>