I typed the attached into ginsh, maybe it helps,
lsolve({a0+x*a1 == y, y - (b0+b1*x) ==0}, {x,y}); {x==(a1-b1)^(-1)*(-a0+b0),y==(a1-b1)^(-1)*(b0*a1-a0*b1)}
You can also the 'collect' expression on a-b to help simplify. Can you give some more information on what you need to do? JP Vera Louise Hauge wrote:
Hi,
I want to compare (or test the equality of) two ex objects which contain symbols. a = a0 + x*a1; b = a0 + a1*x;
If the ex objects are evaluated (symbolically), such that a-b becomes 0, then the test would be finished.
However, how do I evaluate such a expression as a-b symbolically?
Or are there other ways of comparing two such ex objects?
Any suggestions on how to do this?
Thanks,
Vera Louise Hauge
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