7 Aug
2002
7 Aug
'02
7:48 p.m.
Hi! On Wed, Aug 07, 2002 at 06:57:08PM +0200, Alexander Heide wrote:
cout << (1 + a*x + Order(pow(x, 2))).series(x == 0, 2).diff(a) << endl; [...] prints out: 1+(a)*x+Order(x^2)
It seems that no one has bothered to implement this, so I've done it now... Bye, Christian -- / Coding on PowerPC and proud of it \/ http://www.uni-mainz.de/~bauec002/