Re: patch for expansion of log.

Hi. On Fri, Apr 16, 2004 at 06:03:50PM +0000, Chris Dams wrote:

Hello,

I found out that trying to calculate

log(a*x+b*x*x*log(x)).series(x==0,3)

does not terminate. This is because in the function the argument has a pole even if a log(a*x) is subtracted. The attached patch should solve this. With this patch the result of the calculation is

(log(x*a))+(a^(-1)*b*log(x))*x+(-1/2*a^(-2)*b^2*log(x)^2)*x^2+Order(x^3)

as expected.

Your patch has been applied. Thanks! Bye, and nice weekend too, Jens