31 Jul
2013
31 Jul
'13
11:14 a.m.
Dear Alexei,
On Wed, 31 Jul 2013 10:30:26 +0300, Alexei Sheplyakov <alexei.sheplyakov@gmail.com> said: ASh> Hence |Z^A| = exp(Re(A) ln|Z| - Im(A) arg(Z)) = |Z|^Re(A) ASh> exp(-Im(A) arg(Z))
Thanks for pointing out my error. Since, this evaluation can lead to a more complex expression in general, I reduced it to two cases Im(A)=0 or arg(Z=0). The corrected patch is attached. Best wishes, Vladimir -- Vladimir V. Kisil email: kisilv@maths.leeds.ac.uk www: http://www.maths.leeds.ac.uk/~kisilv/ Book: Geometry of Mobius Transformations http://www.worldscientific.com/worldscibooks/10.1142/p835