Dear All,
Consider the code:
#include <iostream>
#include <ginac/ginac.h>
using namespace std;
using namespace GiNaC;
int main()
{
for (int i=0; i < 2; ++i)
(i==0? realsymbol("r") : symbol("s")).dbgprinttree();
return 0;
}
My expectation would be that it first creates a realsymbol r and then
a symbol s. However, the actual output of the programme is:
r (symbol) @0x7fff6e472700, serial=1, hash=0x1689b718, flags=0x6, domain=0
s (symbol) @0x7fff6e472700, serial=2, hash=0x1689b718, flags=0x6, domain=0
That is, in both cases the domain is 0 (complex) and r is not
recognised as a real symbol.
Shall this be corrected or did I misunderstand the concept of (A? B : C)
construct?
Best wishes,
Vladimir
PS Another (less important and more disputable) question: do we want the
debug output for realsymbol/possymbol look like
r (realsymbol) @0x7fff6e472700, serial=1, hash=0x1689b718, flags=0x6, domain=1
p (possymbol) @0x7fff6e472700, serial=1, hash=0x1689b718, flags=0x6, domain=2
to make the class more visible?
--
Vladimir V. Kisil http://www.maths.leeds.ac.uk/~kisilv/
Book: Geometry of Mobius Transformations http://goo.gl/EaG2Vu
Software: Geometry of cycles http://moebinv.sourceforge.net/
Jupyter (Colab): https://github.com/vvkisil/MoebInv-notebooks
Jupyter (CodeOcean): https://codeocean.com/capsule/7952650/tree