[CLN-list] Constructing floating-point numbers

Hello, On Tue, May 25, 2010 at 03:02:56PM -0400, Joshua Friedman wrote:

I say, cln_R x = 3.4; then I computer exp(x), now I convert it to cln_F, Can I do so at any precision.

No. 3.4 is a double precision number, so the result is a double precision too. You have to use cl_float if you need a better precision, i.e. cl_F x = cl_float(34, float_format_t(128))/10; cl_F y = exp(x);

Is exp(x) just a symbolic computation

No, it's a function call. Best regards, Alexei