Re: [CLN-list] const cl_LF operator- (const cl_LF& x, const cl_LF& y)

2 Apr 2008

      Hello,

     Thanks.
     I wrote that letter in order to discuss this problem.And in CLN-1.2.0,I find many "bugs" like this.  

     Alexei Sheplyakov wrote:
...
It *is* wrong, but [sometimes] it happens to work.
I think so. In my opinion,CLN will be modified with the development of compiler GCC.So I suggest that CLN be updated in standard C++. And this will also improve the possibility of migration from GCC to other Compilers.

     Best wishes,                                     
                                                                                                                                               XinJian Zhao

2008-04-02 

zhaoxinjian 

发件人： Alexei Sheplyakov 
发送时间： 2008-04-01  15:49:56 
收件人： CLN discussion list 
抄送： 
主题： Re: [CLN-list] const cl_LF operator- (const cl_LF& x,const cl_LF& y) 

Hello!

On Sat, Mar 29, 2008 at 10:20:00PM +0100, Richard B. Kreckel wrote:
...
zhaoxinjian wrote:
...
I find that the function ( const cl_LF operator- (const cl_LF& x, const cl_LF& y) ) in cl_LF.h and in cl_LF_2mimus.cc is different!
 In cl_LF.h:
 inline const cl_LF operator- (const cl_LF& x, const cl_LF& y)  \
{         \
return LF_LF_minus_LF(x,y);     \
} 
In cl_LF_2mimus.cc :
const cl_LF operator- (const cl_LF& x1, const cl_LF& x2)
{ GEN_LF_OP2(x1,x2,LF_LF_minus_LF,return) }
}  // namespace cln 
Is it wrong?
It is wrong.
...
And Why?
Because it declares the same function to be inline and non-inline, 
which violates the standard (7.1.2.4).
...
It's not wrong.
It *is* wrong, but [sometimes] it happens to work.

Best regards,
Alexei

-- 
All science is either physics or stamp collecting.
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