Re: [CLN-list] const cl_LF operator- (const cl_LF& x, const cl_LF& y)

29 Mar 2008

      Hi!

zhaoxinjian wrote:
...
I find that the function ( const cl_LF operator- (const cl_LF& x, const cl_LF& y) ) in cl_LF.h and in cl_LF_2mimus.cc is different!
 In cl_LF.h:
 inline const cl_LF operator- (const cl_LF& x, const cl_LF& y)  \
{         \
return LF_LF_minus_LF(x,y);     \
} 
In cl_LF_2mimus.cc :
const cl_LF operator- (const cl_LF& x1, const cl_LF& x2)
{ GEN_LF_OP2(x1,x2,LF_LF_minus_LF,return) }
}  // namespace cln 
Is it wrong? And Why?
It's not wrong. The first operator-() is part of a macro. It is an 
optimization, applicable as described in the comment above that macro.

   -richy.
-- 
Richard B. Kreckel
<http://www.ginac.de/~kreckel/>